PAT 1083. List Grades (25)（成绩排序）

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1083. List Grades (25)

时间限制
400 ms
内存限制
65536 kB
代码长度限制
16000 B
判题程序
Standard
作者
CHEN, Yue
Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.

Input Specification:

Each input file contains one test case. Each case is given in the following format:

N
name[1] ID[1] grade[1]
name[2] ID[2] grade[2]
… …
name[N] ID[N] grade[N]
grade1 grade2
where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade’s interval. It is guaranteed that all the grades are distinct.

Output Specification:

For each test case you should output the student records of which the grades are in the given interval [grade1, grade2] and are in non-increasing order. Each student record occupies a line with the student’s name and ID, separated by one space. If there is no student’s grade in that interval, output “NONE” instead.

Sample Input 1:
4
Tom CS000001 59
Joe Math990112 89
Mike CS991301 100
Mary EE990830 95
60 100
Sample Output 1:
Mike CS991301
Mary EE990830
Joe Math990112
Sample Input 2:
2
Jean AA980920 60
Ann CS01 80
90 95
Sample Output 2:
NONE

题目大意

• 1.给你n个学生的名字，id和分数，要你按照分数非递减进行排序，并输出给定分数区间的那些记录。
• 2.保证所有分数都是不同的。
• 3.有就输出名字和id，没有就输出”NONE”。

解题思路

• 1.排序再输出就行了，再用一个bool值判断是否要输出”NONE”就行了。

AC代码

#include<iostream>#include<algorithm>#include<string>#include<vector>using namespace std;struct student{    string name, id;    int grade;};bool cmp(const student &a, const student &b){    return a.grade > b.grade;}int n;int main(){    cin >> n;    vector<student> stu(n);    for (int i = 0; i < n; i++)    {        cin >> stu[i].name >> stu[i].id >> stu[i].grade;    }    int grade1, grade2;    cin >> grade1 >> grade2;    if (!stu.empty())    {        sort(stu.begin(), stu.end(),cmp);        bool flag = false;        for (int i = 0; i < n; i++)        {            ;            if (stu[i].grade<=grade2&&stu[i].grade>=grade1)            {                //判断是否要输出"NONE"                if (!flag)                {                    flag = true;                }                cout << stu[i].name << " " << stu[i].id << endl;            }        }        if (!flag)        {            cout << "NONE" << endl;        }    }    else    {        cout << "NONE" << endl;    }    return 0;}