hdu2055 An easy problem

An easy problem

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 20884    Accepted Submission(s): 13891

Problem Description

we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

 

Input

On the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.

 

Output

for each case, you should the result of y+f(x) on a line.

 

Sample Input

6R 1P 2G 3r 1p 2g 3

 

Sample Output

191810-17-14-4

 

最近心情不是很好，赶紧水一下，以稳定情绪

<span style="font-size:12px;">#include<cstdio>#include<iostream>using namespace std;int main(){int t,f[123];cin>>t;for(int c=1,i='A';i<='Z';c++,i++){f[i]=c;f[i+32]=-c;}while(t--){char x;int y;cin>>x>>y;cout<<y+f[x]<<endl;}return 0;} </span>