2.4version's servlet
来源:互联网 发布:网页视频抓取软件 编辑:程序博客网 时间:2024/06/04 19:39
先创建web project,项目名为test,
在webroot 目录下创建login.jsp文件
login.jsp
<body>
<form action="login">
username:<input type="text" name="username"><br>
password:<input type="password" name="pwd"><br>
<input type="submit">
</form>
</body>
在scr目录下的com.ht.servlet
编写AcountBean.java文件
package com.ht.servlet;
public class AcountBean {
private String username="";
private String password="";
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
}
编写servlet类CheckAccount.java文件
package com.ht.servlet;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.*;
public class CheckAccount extends HttpServlet {
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
HttpSession session = request.getSession();
AcountBean account = new AcountBean();
String username = request.getParameter("username");
String pwd = request.getParameter("pwd");
account.setUsername(username);
account.setPassword(pwd);
if ((username != null) && (username.trim().equals("jsp"))) {
if ((pwd != null) && (pwd.trim().equals("1"))) {
System.out.println("session");
session.setAttribute("account", account);
String logon_suc = "session.jsp";
response.sendRedirect(logon_suc);
return;
}
}
String logon_fail = "fail.jsp";
response.sendRedirect(logon_fail);
return;
}
public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
doGet(request, response);
}
}
在webroot目录下
编写session.jsp文件 成功后跳转
<body>
<%
com.ht.servlet.AcountBean account=(com.ht.servlet.AcountBean)session.getAttribute("account");
%>
username: <%=account.getUsername() %>
<br>
password:<%=account.getPassword() %>
</body>
编写fail.jsp文件 失败后跳转
<body>
Logon Failed <br>
</body>
下面是web.xml文件
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<welcome-file-list><welcome-file>login.jsp</welcome-file></welcome-file-list>
<servlet>
<description>This is the description of my J2EE component</description>
<display-name>This is the display name of my J2EE component</display-name>
<servlet-name>CheckAccount</servlet-name>
<servlet-class>com.ht.servlet.CheckAccount</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>CheckAccount</servlet-name>
<url-pattern>/login</url-pattern>
</servlet-mapping>
</web-app>
通过myeclipse运行 配置tomcat 这里省略。。。
http://127.0.0.1:8080/tset/ 验证察看结果
源码下载http://tel4.800disk.com/?mbsky0618 密码mbsky0618
- 2.4version's servlet
- C++ version's SAX
- My App's Version
- what's servlet?
- [ZT]Java Servlet Specification Version 2.3笔记
- tomcat(5)servlet容器(lastest version)
- dedict's igoogle gadget version 1.4 realesed!
- Teddy's Aspect Weaver Version 0.6
- Teddy's Aspect Weaver Version 0.5
- No valid Qt version set S…
- Get the browser's version info.
- OpenWrt's Release Note and Version info
- servlet-api-2.4.jar) - jar not loaded. See Servlet Spec 2.3, section 9.7.2. Offending class: javax/s
- javax/servlet/ServletContext : Unsupported major.minor version 51.0
- Duke's Bookstore(Servlet 版本)笔记
- Tomcat's Java Servlet Examples Explained
- Welcome to Version 2.0 of theForger's Win32 API Tutorial
- Yoda's Protector Version 1.02 Source Code by ashkbiz
- 黑客基地
- 为什么Java中继承是有害的?
- Oracle中的外连接简单介绍
- UCP Message Structure
- 有关va_list和vsnprintf输出函数的问题
- 2.4version's servlet
- 笑话
- Javascript的IE和Firefox兼容性汇编(转载feng_sundy 的Blog)
- 导入天乙社区BBSCS8到eclipse乱码解决方案
- linux中RamDisk的三种实现方式
- Hibernate3应用小结及问题
- 开心啊
- LAMP学习之旅
- iptables limit 限速备忘