将两个字符转化成一个十六进制数

注：以下代码中默认 UINT8 a=‘3’,UINT8 b=‘F’，就不写函数调用了;

#include<stdio.h>typedef unsigned char UINT8;typedef unsigned short UINT16;UINT8 transform(UINT8 a,UINT8 b){   UINT8 c;   if(a>='0' && a<='9')   {      a=a-'0';    }   else if(a>='A' && a<='F')   {      a=a-'A'+10;     }   else if(a>='a' && a<='f')   {      a=a-'a'+10;   }   if(b>='0' && b<='9')   {      b=b-'0';   }   else if(b>='A' && b<='F')   {      b=b-'A'+10;   }   else if(b>='a' && b<='f')   {      b=b-'a'+10;   }   return (a<<4)|b;}