[Leetcode] Symmetric
来源：互联网 发布：c 比java难 编辑：程序博客网 时间：2024/06/16 12:09
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */class Solution {public: bool isSymmetric(TreeNode* root) { if(root == nullptr) return true; else return inorder(root->left,root->right); } bool inorder(TreeNode* tree1, TreeNode* tree2){ if(tree1 == nullptr && tree2 == nullptr) return true; else if(tree1 == nullptr || tree2 == nullptr) return false; if(tree1->val!=tree2->val) return false; else return inorder(tree1->left,tree2->right) &&inorder(tree1->right,tree2->left); } };对称树应该用中序遍历，我脑子傻了开始用后序。。。
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