python 快速获取图片大小

来源：互联网发布：密度板的甲醛知乎编辑：程序博客网时间：2024/05/02 02:47

实现原理

利用header请求原则,只进行header请求获取图片info,有效缩短时间,减少图片下载解析的过程：

                    url = "http://avatar.csdn.net/0/A/C/1_hi_chen_xingwang.jpg"                    rq = urllib2.Request(url,)                    rq.get_method = lambda:'HEAD'                    rp = urllib2.urlopen(rq,timeout= 10)                    msgs = rp.info().headers                    msg = rp.info()                    size = 0                    # size = msgs.items()[0][1]                    for i in xrange(0,len(msgs)):                        pass                        head = msgs[i][:len('Content-Length')]                        # print head                        if str(head) == "Content-Length":                            pass                            size = msgs[i].split(':')[1]                            # print size                        else:                            pass                            print '------------------------------'                    print "--------->size<---------"                    image_size = int(size)/1024                    print image_size

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