指针练习 1002 将数组a中的n个整数按相反顺序存放

 #include <stdio.h>


int main()
{
int inv(int* x,int n);
int i,a[10]={3,7,9,11,0,6,7,5,4,2};
printf("The original array:\n");
for(i=0;i<10;i++)
printf("%d",a[i]);
printf("\n");
inv(a,10);
printf("The array has been inverted:\n");
for(i=0;i<10;i++)
printf("%d",a[i]);
printf("\n");
    return 0;
}
int inv(int* x,int n)
{
int *p,temp,*i,*j,m=(n-1)/2;
i=x;j=x+n-1;p=x+m;
for(;i<=p;i++,j--)
{
temp=*i;*i=*j;*j=temp;
}
return;
}