HM之基于哈达玛变换的SATD计算

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// 函数功能是计算8×8块的哈达玛变换，并计算其SAD值，m2[8][8]存放最终的变换结果

Int xCalcHADs8x8_ISlice(Pel *piOrg, Int iStrideOrg){Int k, i, j, jj;Int diff[64], m1[8][8], m2[8][8], m3[8][8], iSumHad = 0;//把8×8块像素存放在一维数组中for( k = 0; k < 64; k += 8 ){diff[k+0] = piOrg[0] ;diff[k+1] = piOrg[1] ;diff[k+2] = piOrg[2] ;diff[k+3] = piOrg[3] ;diff[k+4] = piOrg[4] ;diff[k+5] = piOrg[5] ;diff[k+6] = piOrg[6] ;diff[k+7] = piOrg[7] ;piOrg += iStrideOrg; //指针指向下一行}//horizontal 水平变换，计算V=X×H，for (j=0; j < 8; j++){jj = j << 3; //一次算8个，乘8换行m2[j][0] = diff[jj ] + diff[jj+4];m2[j][1] = diff[jj+1] + diff[jj+5];m2[j][2] = diff[jj+2] + diff[jj+6];m2[j][3] = diff[jj+3] + diff[jj+7];m2[j][4] = diff[jj ] - diff[jj+4];m2[j][5] = diff[jj+1] - diff[jj+5];m2[j][6] = diff[jj+2] - diff[jj+6];m2[j][7] = diff[jj+3] - diff[jj+7];m1[j][0] = m2[j][0] + m2[j][2];m1[j][1] = m2[j][1] + m2[j][3];m1[j][2] = m2[j][0] - m2[j][2];m1[j][3] = m2[j][1] - m2[j][3];m1[j][4] = m2[j][4] + m2[j][6];m1[j][5] = m2[j][5] + m2[j][7];m1[j][6] = m2[j][4] - m2[j][6];m1[j][7] = m2[j][5] - m2[j][7];m2[j][0] = m1[j][0] + m1[j][1];m2[j][1] = m1[j][0] - m1[j][1];m2[j][2] = m1[j][2] + m1[j][3];m2[j][3] = m1[j][2] - m1[j][3];m2[j][4] = m1[j][4] + m1[j][5];m2[j][5] = m1[j][4] - m1[j][5];m2[j][6] = m1[j][6] + m1[j][7];m2[j][7] = m1[j][6] - m1[j][7];}//vertical 垂直变换，计算H×Vfor (i=0; i < 8; i++){m3[0][i] = m2[0][i] + m2[4][i];m3[1][i] = m2[1][i] + m2[5][i];m3[2][i] = m2[2][i] + m2[6][i];m3[3][i] = m2[3][i] + m2[7][i];m3[4][i] = m2[0][i] - m2[4][i];m3[5][i] = m2[1][i] - m2[5][i];m3[6][i] = m2[2][i] - m2[6][i];m3[7][i] = m2[3][i] - m2[7][i];m1[0][i] = m3[0][i] + m3[2][i];m1[1][i] = m3[1][i] + m3[3][i];m1[2][i] = m3[0][i] - m3[2][i];m1[3][i] = m3[1][i] - m3[3][i];m1[4][i] = m3[4][i] + m3[6][i];m1[5][i] = m3[5][i] + m3[7][i];m1[6][i] = m3[4][i] - m3[6][i];m1[7][i] = m3[5][i] - m3[7][i];m2[0][i] = m1[0][i] + m1[1][i];m2[1][i] = m1[0][i] - m1[1][i];m2[2][i] = m1[2][i] + m1[3][i];m2[3][i] = m1[2][i] - m1[3][i];m2[4][i] = m1[4][i] + m1[5][i];m2[5][i] = m1[4][i] - m1[5][i];m2[6][i] = m1[6][i] + m1[7][i];m2[7][i] = m1[6][i] - m1[7][i];}for (i = 0; i < 8; i++){for (j = 0; j < 8; j++){iSumHad += abs(m2[i][j]);}}iSumHad -= abs(m2[0][0]);iSumHad =(iSumHad+2)>>2; //除以系数4，并向上取整return(iSumHad);}

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