404. Sum of Left Leaves
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Find the sum of all left leaves in a given binary tree.
Example:
3 / \ 9 20 / \ 15 7There are two left leaves in the binary tree, with values 9 and 15 respectively. Return 24.
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */public class Solution { public int sumOfLeftLeaves(TreeNode root) { if (root == null)return 0;if (root.left != null && root.left.right == null&& root.left.left == null) {return root.left.val + sumOfLeftLeaves(root.right);}return sumOfLeftLeaves(root.left) + sumOfLeftLeaves(root.right); }} 0 0
- 404. Sum of Left Leaves
- 404. Sum of Left Leaves
- 404. Sum of Left Leaves
- 404. Sum of Left Leaves
- 404. Sum of Left Leaves
- 404. Sum of Left Leaves
- 404. Sum of Left Leaves
- 404. Sum of Left Leaves
- 404. Sum of Left Leaves
- 404. Sum of Left Leaves*
- 404. Sum of Left Leaves
- 404. Sum of Left Leaves
- 404. Sum of Left Leaves
- 404. Sum of Left Leaves
- 404. Sum of Left Leaves
- 404. Sum of Left Leaves
- 404. Sum of Left Leaves
- 404. Sum of Left Leaves
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