242. Valid Anagram QuestionEditorial Solution

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原题链接：https://leetcode.com/problems/valid-anagram/

原题：
Given two strings s and t, write a function to determine if t is an anagram of s.

For example,
s = “anagram”, t = “nagaram”, return true.
s = “rat”, t = “car”, return false.

Note:
You may assume the string contains only lowercase alphabets.

Follow up:
What if the inputs contain unicode characters? How would you adapt your solution to such case?

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题意:
给你两个字符串s和t，要你写一个函数判断t是否是s的乱序字符串（即字母元素一样，但是字母顺序可能不一样）

思路：
先判断两字符串长度是否相同，
用一个长度为26的int数组来记录t中出现过的字符个数，然后遍历s判断s中的字母是否在t中都有即可。

AC代码：

class Solution {public:    bool isAnagram(string s, string t) {        int letter[26]={0};        if(s.length()!=t.length()) return false;        for(int i=0;i<t.length();i++){            letter[t[i]-'a']++;        }        for(int i=0;i<s.length();i++){            if(letter[s[i]-'a']==0)            return false;            letter[s[i]-'a']--;        }        return true;    }};

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