1082. Read Number in Chinese

1082. Read Number in Chinese (25)

时间限制

400 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

CHEN, Yue

Given an integer with no more than 9 digits, you are supposed to read it in the traditional Chinese way. Output "Fu" first if it is negative. For example, -123456789 is read as "Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu". Note: zero ("ling") must be handled correctly according to the Chinese tradition. For example, 100800 is "yi Shi Wan ling ba Bai".

Input Specification:

Each input file contains one test case, which gives an integer with no more than 9 digits.

Output Specification:

For each test case, print in a line the Chinese way of reading the number. The characters are separated by a space and there must be no extra space at the end of the line.

Sample Input 1:

-123456789

Sample Output 1:

Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu

Sample Input 2:

100800

Sample Output 2:

yi Shi Wan ling ba Bai

因为位数有限而且不多，就直接处理好了，h万和l(1-999)有类似的地方，注意空格的输出和ling的输出。

要对0这个输入特殊处理一下。

#include<iostream>#include<string>#include<cmath>using namespace std;string num[10]={"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};string unit[5]={"","Shi","Bai","Qian","Wan"};int main(){int n;cin>>n;if(n==0){cout<<"ling";return 0;}if(n<0)cout<<"Fu ";n=abs(n);if(n/100000000)cout<<num[n/100000000]<<" Yi";bool f=n/100000000;n=n%100000000;if(n&&f)cout<<" ";int h=n/10000;bool f0=!f;int op=1000;int cnt=3;while(h){if(h/op){cout<<num[h/op];f0=false;if(cnt)cout<<" "<<unit[cnt];if(h%op)cout<<" ";}else if(!f0){cout<<"ling ";f0=true;}h=h%op;op=op/10;cnt--;}if(n/10000)cout<<" Wan";int l=n%10000;if(l&&n/10000)cout<<" ";f0=!(f||n/10000);op=1000;cnt=3;while(l){if(l/op){cout<<num[l/op];f0=false;if(cnt)cout<<" "<<unit[cnt];if(l%op)cout<<" ";}else if(!f0){cout<<"ling ";f0=true;}l=l%op;op=op/10;cnt--;}}