UVA 11388 GCD LCM
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水题
#include<stdio.h>#include<iostream>#include<math.h>#include<string.h>#include<iomanip>#include<stdlib.h>#include<ctype.h>#include<algorithm>#include<deque>#include<functional>#include<iterator>#include<vector>#include<list>#include<map>#include<queue>#include<set>#include<stack>#include<sstream>#define CPY(A,B)memcpy(A,B,sizeof(A))typedef long long LL;typedef unsigned long long uLL;const int MOD=1e9+7;const int INF=0x3f3f3f3f;const LL INFF=0x3f3f3f3f3f3f3f3fLL;const double EPS=1e-9;const double OO=1e20;const double PI=acos (-1.0);int dx[]= {0,1,0,-1};int dy[]= {1,0,-1,0};int gcd (const LL &a,const LL &b) {return b==0?a:gcd (b,a%b);}using namespace std;int main() { int n,G,L; while (scanf ("%d",&n) !=EOF) for (int t=1; t<=n; ++t) { scanf ("%d%d",&G,&L); if (L%G==0) { printf ("%d %d\n",G,L); } else {printf ("-1\n");} } return 0;}
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