编写JavaApplication，求出e=1+1/1!+1/2!+1/3!+···+1/n！···的近似值，要求误差小于0.00001

class Conversion_E{    static int jc(int n){         if(n == 0 || n == 1)             return 1;         else             return n*jc(n - 1);    }        public static void main(String []args){        double e = 1;        for(int i = 1; i < 100; i++){            e += 1.00000/jc(i);            if(0.00001 > Math.E - e){                System.out.println("n最小为" + i + "时，误差小于0.00001，它的值为：" + e);                break;            }        }    }}