LeetCode 387. First Unique Character in a String 题解(C++)
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LeetCode 387. First Unique Character in a String 题解(C++)
题目描述
- Given a string, find the first non-repeating character in it and return it’s index. If it doesn’t exist, return -1.
举例
s = “leetcode”
return 0.s = “loveleetcode”,
return 2.
补充
- You may assume the string contain only lowercase letters.
思路
- 定义一个包含26个整数的数组cNum,用于保存每个字母出现的次数,遍历字符串s,将每个字母出现的次数记录在数组cNum里;
- 再次遍历字符串,依照字符串的顺序检查每个字母是否只出现了一次,若该字母只出现了一次,则返回其位置;
- 若遍历完成扔找不到位置,则证明不存在,返回-1。
代码
class Solution {public: int firstUniqChar(string s) { int cNum[26] = {0}; for (auto c : s) { ++cNum[c - 'a']; } for (int i = 0; i < s.size(); ++i) { if (cNum[s[i] - 'a'] == 1) { return i; } } return -1; }};
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