Htm5 求同时被3和7整除的数

来源：互联网发布：csol买淘宝欢乐积分编辑：程序博客网时间：2024/04/28 06:42

<!doctype html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>求某范围能被3和7整除的数</title>
<script type="text/javascript" defer>
var str = " ";
var begin;
var end;
var count=0;

function jisuan(num) {//返回能同时被3和7整除的数
if((num % 3 == 0) && (num % 7 == 0)){
return num;
}
else{
return false;
}
}

function method(){
//获取输入框的值
begin = document.getElementById("begin").value;
end = document.getElementById("end").value;
var i;
//循环打印输出
for(i=begin;i<=end;i++){
if(jisuan(i)){
str +=i + "&nbsp";
document.getElementById("result").innerHTML = str;
count ++;
//每输出十个数换行
if(count % 10 == 0){
str = str + "<br> ";
}
}

}
}
</script>
</head>
<body onload="">
<h3>求某范围能被3和7整除的数</h3>
<div>
<span>开始范围：</span>
<input type="text" id ="begin" value="1"><br>

<span>结束范围：</span>
<input type="text" id ="end" value="22"><br>

<button onclick="method();">计算</button>

</div>
<hr>

<div id="result">
</div>
</body>

</html>

0 0