153. Find Minimum in Rotated Sorted Array
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153. Find Minimum in Rotated Sorted Array
Suppose a sorted array is rotated at some pivot unknown to you beforehand.
(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).
Find the minimum element.
You may assume no duplicate exists in the array.
思路：如果nums[mid]<nums[high]，说明后半部分是顺序的，且最小值在[start ... mid]之间。否则，说明有反转，最小值在后半区间。
<span style="font-size:18px;">class Solution { int binary_search(vector<int> & nums, int s, int e) { if(nums[s]<=nums[e]) return nums[s]; int mid=s+(e-s)/2; if(nums[mid]>nums[e]) return binary_search(nums,mid+1,e); else return binary_search(nums,s,mid); }public: int findMin(vector<int>& nums) { int n=nums.size(); return binary_search(nums,0,n-1); }};</span> 0 0
- 153. Find Minimum in Rotated Sorted Array
- 153. Find Minimum in Rotated Sorted Array
- 153. Find Minimum in Rotated Sorted Array
- 153. Find Minimum in Rotated Sorted Array
- 153. Find Minimum in Rotated Sorted Array
- 153. Find Minimum in Rotated Sorted Array
- 153. Find Minimum in Rotated Sorted Array
- 153. Find Minimum in Rotated Sorted Array
- 153. Find Minimum in Rotated Sorted Array
- 153. Find Minimum in Rotated Sorted Array
- 153. Find Minimum in Rotated Sorted Array
- 153. Find Minimum in Rotated Sorted Array
- 153. Find Minimum in Rotated Sorted Array
- 153. Find Minimum in Rotated Sorted Array **
- 153. Find Minimum in Rotated Sorted Array
- 153. Find Minimum in Rotated Sorted Array
- 153. Find Minimum in Rotated Sorted Array
- 153. Find Minimum in Rotated Sorted Array
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