window.open()参数传递及获取

20161021

1、带参数打开新窗口

$window.open("/bdfence/bdfence-division/bdfence.html?vehicleId="+ id  );

2、获取参数

var afterUrl =  window.location.search.substring(1);(问号以后的字符串)

var afterEqual = afterUrl.substring(afterUrl.indexof('=')+1).toUpperCase();(等号以后的字符串，及你所要的参数)