HDU ACM 11 2064 汉诺塔III

题目很简单。但是有坑

#include <iostream>using namespace std;int main(){__int64 n, Lu[35];while (cin >> n){Lu[1] = 2;for (int i = 2; i <= n; i++)Lu[i] = 3 * Lu[i - 1] + 2;cout << Lu[n] << endl;}return 0;}