幸运之星递归实现

#include "stdafx.h"//VS预编译头#include<iostream>using namespace std;//递归奇数int odd(int n) {if (n == 1) {return 1;}else{return odd(n / 2) * 2;}}int main(){int n;//总人数和m值int m;cin >> n >> m;cout << odd(n);cout << " ";//格式需要一个空格int m_out = 0;//m值时候的输出for (int i = 2; i <= n; i++) {m_out = (m_out + m) % i;}cout << m_out + 1;    return 0;}