纯JS脚本1k大小的3D圣诞树

来源：互联网发布：小白淘宝屋大头鞋编织编辑：程序博客网时间：2024/04/29 13:34

<html>  <head>    <title>Merry Christmas!</title>    <meta charset="utf-8" />  </head>  <body>    <canvas id="c"></canvas><script>      var b = document.body;      var c = document.getElementsByTagName('canvas')[0];      var a = c.getContext('2d');      document.body.clientWidth;     </script>    <script>      M=Math;  Q=M.random;  J=[];U=16;  T=M.sin;  E=M.sqrt;  for(O=k=0;x=z=j=i=k<200;)  with(M[k]=k?c.cloneNode(0):c){  width=height=k?32:W=446;  with(getContext('2d'))  if(k>10|!k)  for(font='60px Impact',V='rgba(';I=i*U,fillStyle=k?k==13?V+'205,205,215,.15)':V+(147+I)+','+(k%2?128+I:0)+','+I+',.5)':'#cca',i<7;)  beginPath(fill(arc(U-i/3,24-i/2,k==13?4-(i++)/2:8-i++,0,M.PI*2,1)));  else for(;x=T(i),y=Q()*2-1,D=x*x+y*y,B=E(D-x/.9-1.5*y+1),R=67*(B+1)*(L=k/9+.8)>>1,i++<W;)  if(D<1)  beginPath(strokeStyle=V+R+','+(R+B*L>>0)+',40,.1)'),moveTo(U+x*8,U+y*8),lineTo(U+x*U,U+y*U),stroke();  for(y=H=k+E(k++)*25,R=Q()*W;P=3,j<H;)  J[O++]=[x+=T(R)*P+Q()*6-3,y+=Q()*U-8,z+=T(R-11)*P+Q()*6-3,j/H*20+((j+=U)>H&Q()>.8?Q(P=9)*4:0)>>1]  }  setInterval(function G(m,l){  A=T(D-11);if(l)return(m[2]-l[2])*A+(l[0]-m[0])*T(D);  a.clearRect(0,0,W,W);  J.sort(G);for(i=0;L=J[i++];  a.drawImage(M[L[3]+1],207+L[0]*A+L[2]*T(D)>>0,L[1]>>1)){  if(i==2e3)a.fillText('Merry Christmas!',U,345);  if(!(i%7))  a.drawImage(M[13],((157*(i*i)+T(D*5+i*i)*5)%W)>>0,((113*i+(D*i)/60)%(290+i/99))>>0);}D+=.02},1)    </script>  </body></html>

实现原理：http://www.romancortes.com

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