关于USACO

这是第一道。。。以这道题目举例
Your Ride Is Here

It is a well-known fact that behind every good comet is a UFO. These UFOs often come to collect loyal supporters from here on Earth. Unfortunately, they only have room to pick up one group of followers on each trip. They do, however, let the groups know ahead of time which will be picked up for each comet by a clever scheme: they pick a name for the comet which, along with the name of the group, can be used to determine if it is a particular group’s turn to go (who do you think names the comets?). The details of the matching scheme are given below; your job is to write a program which takes the names of a group and a comet and then determines whether the group should go with the UFO behind that comet.

Both the name of the group and the name of the comet are converted into a number in the following manner: the final number is just the product of all the letters in the name, where “A” is 1 and “Z” is 26. For instance, the group “USACO” would be 21 * 19 * 1 * 3 * 15 = 17955. If the group’s number mod 47 is the same as the comet’s number mod 47, then you need to tell the group to get ready! (Remember that “a mod b” is the remainder left over after dividing a by b; 34 mod 10 is 4.)

Write a program which reads in the name of the comet and the name of the group and figures out whether according to the above scheme the names are a match, printing “GO” if they match and “STAY” if not. The names of the groups and the comets will be a string of capital letters with no spaces or punctuation, up to 6 characters long.

Examples:

Input Output
COMETQ
HVNGAT

GO
ABSTAR
USACO
STAY

PROGRAM NAME: ride
This means that you fill in your header with:
PROG: ride
WARNING: You must have ‘ride’ in this field or the wrong test data (or no test data) will be used.
INPUT FORMAT

Line 1: An upper case character string of length 1..6 that is the name of the comet.
Line 2: An upper case character string of length 1..6 that is the name of the group.

NOTE: The input file has a newline at the end of each line but does not have a “return”. Sometimes, programmers code for the Windows paradigm of “return” followed by “newline”; don’t do that! Use simple input routines like “readln” (for Pascal) and, for C/C++, “fscanf” and “fid>>string”.

NOTE 2: Because of the extra characters, be sure to leave enough room for a ‘newline’ (also notated as ‘\n’) and an end of string character (‘\0’) if your language uses it (as C and C++ do). This means you need eight characters of room instead of six.

SAMPLE INPUT (file ride.in)
COMETQ
HVNGAT

OUTPUT FORMAT
A single line containing either the word “GO” or the word “STAY”.
SAMPLE OUTPUT (file ride.out)
GO

OUTPUT EXPLANATION
Converting the letters to numbers:

C O M E T Q
3 15 13 5 20 17

H V N G A T
8 22 14 7 1 20
then calculate the product mod 47: 3 * 15 * 13 * 5 * 20 * 17 = 994500 mod 47 = 27
8 * 22 * 14 * 7 * 1 * 20 = 344960 mod 47 = 27

Because both products evaluate to 27 (when modded by 47), the mission is ‘GO’.

中文翻译
Your Ride Is Here
你要乘坐的飞碟在这里
译 by tim green
一个众所周知的事实，在每一慧星后面是一个不明飞行物UFO。 这些不明飞行物时常来收集来自在地球上忠诚的支持者。 不幸地，他们的空间在每次旅行只能带上一群支持者。 他们要做的是用一种聪明的方案让每一个团体人被慧星带走。 他们为每个慧星起了一个名字，通过这些名字来决定一个团体是不是特定的慧星带走。 那个相配方案的细节在下面被给出； 你的工作要写一个程序来通过团体的名字和彗星的名字来决定一个组是否应该与在那一颗慧星后面的不明飞行物搭配。 团体的名字和慧星的名字都以下列各项方式转换成一个数字: 这个最后的数字代表名字中所有字母的信息，”A” 是 1 和 “Z” 是 26。 举例来说，团体 “USACO” 会是 21*19*1*3*15=17955 。 如果团体的数字 mod 47 等于慧星的数字 mod 47,那么你要告诉这个团体准备好被带走 ! 写一个程序读入慧星的名字和团体的名字，如果搭配打印”GO”否者打印”STAY” 团体的名字和慧星的名字将会是有没有空格或标点的一串大写字母（不超过6个字母），
Examples:
Input Output
COMETQ

HVNGAT GO
ABSTAR

USACO STAY
PROGRAM NAME： ride
INPUT FORMAT
第 1 行: 彗星的名字（一个长度为1到6的字符串）
第 2 行: 团体的名字（一个长度为1到6的字符串）
SAMPLE INPUT （file ride.in）
COMETQ
HVNGAT
OUTPUT FORMAT
单独一行包含”STAR”或”GO”.
SAMPLE OUTPUT (file ride.out)
GO

注意点
1.首先这个提交是要用文件，，，就像正规考试一样，cpp文件他有给
文件名，比如这个就是ride,,读入文件就是ride.in,ride.out..这个和一般的OJ网站不同。。。
2.这个需要在代码前写上一些东西，比如这个AC的代码
/*
ID:**就是你的id
LANG:C++
TASK:ride
*/
ID：就是你的ID
LANG：要大些
TASK：就是问题名字

/*ID:****就是你的idLANG:C++TASK:ride */#include<iostream>#include<cstdio>#include<cstring>using namespace std;char s1[8],s2[8];const int mod=47;int main(){    freopen("ride.in","r",stdin);    freopen("ride.out","w",stdout);    scanf("%s",s1);    scanf("%s",s2);    int ans1=1,ans2=1;    int a=strlen(s1),b=strlen(s2);    for(int i = 0; i<a;i++)        ans1=ans1 * (s1[i]-'A'+1)%mod;    for(int i = 0; i<b;i++)        ans2=ans2 * (s2[i]-'A'+1)%mod;    if(ans1==ans2)printf("GO\n");    else printf("STAY\n");    return 0;}

其实这个网站很好的地方是你错了那组数据他会给你，很不错，QAQ，不过不要直接printf,,,会被封号的。。。。

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