405. Convert a Number to Hexadecimal
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原题网址:https://leetcode.com/problems/convert-a-number-to-hexadecimal/
Given an integer, write an algorithm to convert it to hexadecimal. For negative integer, two’s complement method is used.
Note:
- All letters in hexadecimal (
a-f
) must be in lowercase. - The hexadecimal string must not contain extra leading
0
s. If the number is zero, it is represented by a single zero character'0'
; otherwise, the first character in the hexadecimal string will not be the zero character. - The given number is guaranteed to fit within the range of a 32-bit signed integer.
- You must not use any method provided by the library which converts/formats the number to hex directly.
Example 1:
Input:26Output:"1a"
Example 2:
Input:-1Output:"ffffffff"
方法:通过二进制转换。
public class Solution { private char[] hex(int num) { char[] hex = new char[8]; for(int i = 7; i >= 0; i--) { hex[i] = (num & 0b1111) < 10 ? (char)('0' + (num & 0b1111)) : (char)('a' + (num & 0b1111) - 10); num >>>= 4; } return hex; } public String toHex(int num) { char[] hex = hex(num); StringBuilder sb = new StringBuilder(); boolean nonzero = false; for(int i = 0; i < hex.length; i++) { if (hex[i] != '0') { nonzero = true; } if (nonzero) { sb.append(hex[i]); } } if (sb.length() == 0) { sb.append('0'); } return sb.toString(); }}
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