1061. Dating (20)解题报告

来源：互联网发布：谭浩强c语言第四版答案编辑：程序博客网时间：2024/05/02 01:39

#define _CRT_SECURE_NO_WARNINGS#include <cstdio>#include <cstdlib>#include <cstring>#include <cctype>#define N 100int main(void) {    char days[7][7] = { "MON", "TUE","WED","THU","FRI","SAT","SUN" };    char str1[N], str2[N], str3[N], str4[N];    scanf("%s %s %s %s", str1, str2, str3, str4);    char first, sec;    int i, third;    for (i = 0; i < strlen(str1) && i < strlen(str2); i++) {        if (str1[i] == str2[i] && str1[i] >= 'A' && str1[i] <= 'G') {            first = str1[i];            break;        }    }    for (i++; i < strlen(str1) && i < strlen(str2); i++) {        if (str1[i] == str2[i] && ((str1[i] >= 'A' && str1[i] <= 'N') || isdigit(str1[i]))) {            sec = str1[i];            break;        }    }    for (i = 0; i < strlen(str3) && i < strlen(str4); i++) {        if (str3[i] == str4[i] && isalpha(str4[i])) {            third = i;            break;        }    }    printf("%s %02d:%02d\n", days[first - 'A'], sec >= '0' && sec <= '9' ? sec - '0' : sec - 'A' + 10, third);    return 0;}

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