LeeCode 58. Length of Last Word 计算字符串的最后的一个单词的长度

题目要求:
Given a string s consists of upper/lower-case alphabets and empty space characters ’ ‘, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example,
Given s = “Hello World”,
return 5.

说明:
记住使用 s.trim()方法用于将字符串前后的空格去掉

public class solution {    public int lengthOfLastWord(String s) {        //使用数组的方式进行处理        s = s.trim();   // s.trim() 除去字符串前后的所有的空格        if(s.isEmpty()) return 0;        String[] strarr = s.split(" ");        String strx= strarr[strarr.length - 1];        return strarr[strarr.length - 1].length();    }}