1065. A+B and C (64bit) (20)

Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C.

Input Specification:

The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:

For each test case, output in one line “Case #X: true” if A+B>C, or “Case #X: false” otherwise, where X is the case number (starting from 1).

Sample Input:
3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0
Sample Output:
Case #1: false
Case #2: true
Case #3: false

考虑溢出即可.

#include <iostream>  using namespace std;bool compare(long long int &a, long long int &b, long long int &c){    long long int res = a + b;    if (a > 0 && b > 0 && res <= 0)        return true;    if (a < 0 && b < 0 && res >= 0)        return false;    return res > c;}int main(){    int N;    long long int a, b, c;    cin >> N;    for (int i = 0; i < N; ++i) {        cin >> a >> b >> c;        if (compare(a, b, c)) {            printf("Case #%d: true\n", i + 1);        }        else {            printf("Case #%d: false\n", i + 1);        }    }    return 0;}