springmvc中验证框架

来源：互联网发布：移动的网络电视怎么样编辑：程序博客网时间：2024/05/22 10:54

实体类Person.java（在属性或get方法上加注解）

package com.luohao.entity;
 
import javax.validation.constraints.Pattern;
 
import org.hibernate.validator.constraints.Length;
 
public class Person {
 
@Pattern(regexp="^\\w{6,10}$",message="用户名必须是字母")
private String userName;
@Length(min=6,max=20,message="密码必须是6-20位")
private String passWord;
 
public String getUserName() {
return userName;
}
 
public void setUserName(String userName) {
this.userName = userName;
}
 
public String getPassWord() {
return passWord;
}
 
public void setPassWord(String passWord) {
this.passWord = passWord;
}
  
}

controller中的java类

@RequestMapping("/login")
public ModelAndView login(@Valid @ModelAttribute("person") Person person,BindingResult bindingResult) {
//如果参数和表单的name相同就不用注解表明这是参数
if (bindingResult.hasErrors()) {
ModelAndView mav = new ModelAndView();
Map<String,Object> map = new HashMap<String, Object>();
List<FieldError> errors = bindingResult.getFieldErrors();
for (FieldError err : errors) {
map.put(err.getField(), err.getDefaultMessage());
}
mav.addObject("fieldErrors",map);
mav.setViewName("../login.jsp");
return mav;
}else {
return new ModelAndView("../index.jsp") ;
}
}

jsp页面

 <body>
    <form action="home/login.do" method="post">
    用户名:<input type="text" name = "userName" />
    ${fieldErrors["userName"]}<br>
    密&nbsp;码:<input type="password" name = "passWord" />
    ${fieldErrors["passWord"]}<br>
    <input type="submit" value="提交" />
    </form>
  </body>

需要用到的数据验证包:

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