385. Mini Parser

Given a nested list of integers represented as a string, implement a parser to deserialize it.

Each element is either an integer, or a list -- whose elements may also be integers or other lists.

Note: You may assume that the string is well-formed:

• String is non-empty.
• String does not contain white spaces.
• String contains only digits 0-9, [, - ,, ].

Example 1:

Given s = "324",You should return a NestedInteger object which contains a single integer 324.

Example 2:

Given s = "[123,[456,[789]]]",Return a NestedInteger object containing a nested list with 2 elements:1. An integer containing value 123.2. A nested list containing two elements:    i.  An integer containing value 456.    ii. A nested list with one element:         a. An integer containing value 789.

需要一层一层剥开来构造NestedInteger，如果s不带有括号，例如s="324"，s="573,829"等形式，表明NestedInteger没有内嵌，直接以逗号分割解析成int类型去构造单一的NestedInteger并塞入当前NestedInteger即可。如果s带有括号，表明至少有一个内嵌NestedInteger，需要区分一下s="324"和s="[324]"的情况，前者表示单一的NestedInteger，其数值为324，后者表示一个NestedInteger没有值，只含有一个内嵌的NestedInteger对象，内嵌对象的值为324.

s带括号，先把最外层的括号去除，例如"[123,[456,336,[789]]]"，第一步变成"123,[456,336,[789]]"，这样用不带括号的部分分别构建NestedInteger，并塞入当前NestedInteger，其余部分递归构造一个复合的NestedInteger，然后同样塞入当前NestedInteger

取出递归构造的部分“[456,336,[789]]”需要栈的帮助，遇到“[” 入栈，遇到"]"出栈，如果当前出栈导致栈空的话就把栈弹空，这样就找到了相应的最左边的"["匹配，把这一部分作为参数递归传递。

另外数字的分割以“,”为分隔符，如果当前栈空，两个","之间的数字应该拿出来构造一个单独的NestedInteger并塞入当前NestedInteger，如果栈不空，则表明正在检索复合部分，忽略分割操作。

/** * // This is the interface that allows for creating nested lists. * // You should not implement it, or speculate about its implementation * public interface NestedInteger { *     // Constructor initializes an empty nested list. *     public NestedInteger(); * *     // Constructor initializes a single integer. *     public NestedInteger(int value); * *     // @return true if this NestedInteger holds a single integer, rather than a nested list. *     public boolean isInteger(); * *     // @return the single integer that this NestedInteger holds, if it holds a single integer *     // Return null if this NestedInteger holds a nested list *     public Integer getInteger(); * *     // Set this NestedInteger to hold a single integer. *     public void setInteger(int value); * *     // Set this NestedInteger to hold a nested list and adds a nested integer to it. *     public void add(NestedInteger ni); * *     // @return the nested list that this NestedInteger holds, if it holds a nested list *     // Return null if this NestedInteger holds a single integer *     public List<NestedInteger> getList(); * } */public class Solution {    public NestedInteger deserialize(String s){int len=s.length();Stack<Integer> stack=new Stack<>();int start=0,end=len-1;if(s.charAt(0)=='['){start=1;end=len-2;}else {return new NestedInteger(Integer.parseInt(s));}NestedInteger nestint=new NestedInteger();int last=start-1,now=start;int left=0;for(int i=start;i<=end;i++){char c=s.charAt(i);if(c==','){if(left==0){now=i;if(last+1!=now)nestint.add(new NestedInteger(Integer.parseInt(s.substring(last+1,now))));last=now;}else {}}else if (c=='['){stack.push(i);left++;}else if(c==']'){left--;if(left==0){while(stack.size()>1)stack.pop();nestint.add(deserialize(s.substring(stack.pop(), i+1)));last=i;}}}if(last!=end)nestint.add(new NestedInteger(Integer.parseInt(s.substring(last+1,end+1))));return nestint;}}