页面回车事件点击跳转

<input class="snasub" type="button" value="提交" onclick="return question()" id="button">

document.onkeydown = function (e) {    var theEvent = window.event || e;    var code = theEvent.keyCode || theEvent.which;    if (co== 13)    {$("#button").click();    }}

如果是a标签：

$("#button").click();只是点击不跳转（jquery）document.getElementById("Jump").click();点击加跳转（js）