emoji字符串转化

来源：互联网发布：淘宝店名可以改几次编辑：程序博客网时间：2024/05/17 05:11
/** * 检测是否有emoji字符 *  * @param source * @return 一旦含有就抛出 */public class EmojiFilter {public static boolean containsEmoji(String source) {if (StringUtils.isBlank(source)) {return false;}int len = source.length();for (int i = 0; i < len; i++) {char codePoint = source.charAt(i);if (isEmojiCharacter(codePoint)) {// do nothing，判断到了这里表明，确认有表情字符return true;}}return false;}private static boolean isEmojiCharacter(char codePoint) {return (codePoint == 0x0) || (codePoint == 0x9) || (codePoint == 0xA)|| (codePoint == 0xD)|| ((codePoint >= 0x20) && (codePoint <= 0xD7FF))|| ((codePoint >= 0xE000) && (codePoint <= 0xFFFD))|| ((codePoint >= 0x10000) && (codePoint <= 0x10FFFF));}/** * 过滤emoji 或者 其他非文字类型的字符 *  * @param source * @return */public static String filterEmoji(String source) {if (!containsEmoji(source)) {return source;// 如果不包含，直接返回}// 到这里铁定包含StringBuilder buf = null;int len = source.length();for (int i = 0; i < len; i++) {char codePoint = source.charAt(i);if (isEmojiCharacter(codePoint)) {if (buf == null) {buf = new StringBuilder(source.length());}buf.append(codePoint);} else {}}if (buf == null) {return source;// 如果没有找到 emoji表情，则返回源字符串} else {if (buf.length() == len) {// 这里的意义在于尽可能少的toString，因为会重新生成字符串buf = null;return source;} else {return buf.toString();}}}public static void main(String[] args) {EmojiFilter.filterEmoji("昵称");}}
0 0