interleaving String

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题意：给定三个序列S1,S2,S3,对于S1,S2和S3比较，看S1、S2是否是和S3间隔排序的，譬如，S1 = “aabcc”，S2=”dbbca”，S3=”aadbbcbcac”，则是满足条件的。
思路：动规。维护数组dp[s1.length][s2.length]。先初始化dp数组，再进行判断。
代码：

package com.interLeaving;public class InterLeaving {    public boolean isInterLeaving(String s1 ,String s2 , String s3) {        if(s1.length() + s2.length() != s3.length())  return false;        boolean[][] dp = new boolean[s1.length()+1][s2.length()+1];        for (int i = 1; i <= s1.length() && s1.charAt(i-1) == s3.charAt(i-1); i++)            dp[i][0] = true;        for (int j = 1; j <= s2.length() && s2.charAt(j-1) == s3.charAt(j-1); j++)             dp[0][j] = true;        for(int i = 1 ; i <= s1.length() ; i++){            for(int j =  1 ; j <= s2.length() ; j++){                char c = s3.charAt(i+j-1);                if(c == s1.charAt(i-1) && dp[i-1][j])                    dp[i][j] = true;                if(c == s2.charAt(j-1) && dp[i][j-1])                    dp[i][j] = true;            }        }        return dp[s1.length()][s2.length()];    }    public static void main(String[] args) {        String s1 = "aabcc";        String s2 = "dbbca";        String s3 = "aadbbcbcac";        System.out.println(new InterLeaving().isInterLeaving(s1, s2, s3));    }}

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