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来源：互联网发布：cocos2dx 脏矩形算法编辑：程序博客网时间：2024/04/27 22:28

      java班课作业    //写一个计算器小程序    //实现+-*/ 四个功能    //随便输入两个数运算即可

import java.util.Scanner;

public class jisuanqi {

public static void main(String[] args){    //写一个计算器小程序    //实现+-*/ 四个功能    //随便输入两个数运算即可        boolean bol = true;        while(bol){        double i,j;        int n,m;        Scanner sca1 = new Scanner(System.in);        Scanner sca2 = new Scanner(System.in);        Scanner sca3 = new Scanner(System.in);        Scanner sca4 = new Scanner(System.in);        System.out.println("请输入第一个数");        i = sca1.nextDouble();        System.out.println("请输入第二个数");        j = sca2.nextDouble();        System.out.println("请输入要运算的功能");        System.out.println("1,加法");        System.out.println("2，减法");        System.out.println("3，乘法");        System.out.println("4，除法");        n = sca3.nextInt();            switch (n) {            case 1:                System.out.println("结果是"+(i+j));                break;            case 2:                System.out.println("结果是"+(i-j));                break;            case 3:                System.out.println("结果是"+(i*j));                break;            case 4:                System.out.println("结果是"+(i/j));                break;            default:                System.out.println("功能选择错误，请输入2重新进行运算");                break;            }            System.out.println("输入1,退出计算器");            System.out.println("输入2，继续进行计算");            m = sca4.nextInt();            switch (m) {            case 1:                bol = false;                break;            case 2:                bol = true;                break;            default:                System.out.println("请输入正确的数字");                break;            }        }        }    }

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