Mysql-left join,right join,inner join
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下面是例子分析
表A记录如下:
1.left join(左联接)
sql语句如下:
left join是以A表的记录为基础的,A可以看成左表,B可以看成右表,left join是以左表为准的.
换句话说,左表(A)的记录将会全部表示出来,而右表(B)只会显示符合搜索条件的记录(例子中为: A.aID = B.bID).
B表记录不足的地方均为NULL.
sql语句如下:
很明显,这里只显示出了 A.aID = B.bID的记录.这说明inner join并不以谁为基础,它只显示符合条件的记录.
表A记录如下:
aID aNum 1 a20050111 2 a20050112 3 a20050113 4 a20050114 5 a20050115表B记录如下:
bID bName 1 2006032401 2 2006032402 3 2006032403 4 2006032404 8 2006032408创建这两个表SQL语句如下:
CREATE TABLE a aID int( 1 ) AUTO_INCREMENT PRIMARY KEY , aNum char( 20 ) ) CREATE TABLE b( bID int( 1 ) NOT NULL AUTO_INCREMENT PRIMARY KEY , bName char( 20 ) ) INSERT INTO a VALUES ( 1, 'a20050111' ) , ( 2, 'a20050112' ) , ( 3, 'a20050113' ) , ( 4, 'a20050114' ) , ( 5, 'a20050115' ) ; INSERT INTO b VALUES ( 1, ' 2006032401' ) , ( 2, '2006032402' ) , ( 3, '2006032403' ) , ( 4, '2006032404' ) , ( 8, '2006032408' ) ;实验如下:
1.left join(左联接)
sql语句如下:
SELECT * FROM a LEFT JOIN b ON a.aID =b.bID结果如下:
aID aNum bID bName 1 a20050111 1 2006032401 2 a20050112 2 2006032402 3 a20050113 3 2006032403 4 a20050114 4 2006032404 5 a20050115 NULL NULL结果说明:
left join是以A表的记录为基础的,A可以看成左表,B可以看成右表,left join是以左表为准的.
换句话说,左表(A)的记录将会全部表示出来,而右表(B)只会显示符合搜索条件的记录(例子中为: A.aID = B.bID).
B表记录不足的地方均为NULL.
2.right join(右联接)
sql语句如下:SELECT * FROM a RIGHT JOING b ON a.aID = b.bID结果如下:
aID aNum bID bName 1 a20050111 1 2006032401 2 a20050112 2 2006032402 3 a20050113 3 2006032403 4 a20050114 4 2006032404 NULL NULL 8 2006032408结果说明:
仔细观察一下,就会发现,和left join的结果刚好相反,这次是以右表(B)为基础的,A表不足的地方用NULL填充.
sql语句如下:
SELECT * FROM a INNER JOIN b ON a.aID =b.bID等同于以下SQL句:
SELECT * FROM a,b WHERE a.aID = b.bID结果如下:
aID aNum bID bName 1 a20050111 1 2006032401 2 a20050112 2 2006032402 3 a20050113 3 2006032403 4 a20050114 4 2006032404结果说明:
很明显,这里只显示出了 A.aID = B.bID的记录.这说明inner join并不以谁为基础,它只显示符合条件的记录.
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