HDU1039 Easier Done Than Said?

题目链接：HDU1039

/*    题目大意：验证所设密码可否接受，要求满足以下三个条件：                                1、必须包含元音                                2、三个连续的字母不能同时为元音或者辅音                                3、两个连续的字母不能相同，其中"ee"."oo"除外*/#include <bits/stdc++.h>using namespace std;int main() {    string s;    while (cin >> s && s != "end") {        int flag = 0;        int p = s.size();        for (int i = 0; i<p; i++) {            if (s[i] == 'a' || s[i] == 'e' || s[i] == 'i' || s[i] == 'o' || s[i] == 'u')    flag = 1;        }        int flag1 = 0;        for (int i = 2; i<p; i++) {            if ((s[i] == 'a' || s[i] == 'e' || s[i] == 'i' || s[i] == 'o' || s[i] == 'u') && ((s[i-1] == 'a' || s[i-1] == 'e' || s[i-1] == 'i' || s[i-1] == 'o' || s[i-1] == 'u')) && (s[i-2] == 'a' || s[i-2] == 'e' || s[i-2] == 'i' || s[i-2] == 'o' || s[i-2] == 'u'))                 flag1 = 1;            else if ((s[i] != 'a' && s[i] != 'e' && s[i] != 'i' && s[i] != 'o' && s[i] != 'u') && ((s[i-1] != 'a' && s[i-1] != 'e' && s[i-1] != 'i' && s[i-1] != 'o' && s[i-1] != 'u')) && (s[i-2] != 'a' && s[i-2] != 'e' && s[i-2] != 'i' && s[i-2] != 'o' && s[i-2] != 'u'))                flag1 = 1;        }        int flag2 = 0;        for (int i = 1; i<p; i++) {            if (s[i] == s[i-1] && (s[i] != 'e'&& s[i] != 'o')) flag2 = 1;        }        //cout << flag << flag1 <<flag2 <<endl;        if (flag == 1 && flag1 == 0 && flag2 == 0)  cout << "<" << s << ">" << " is acceptable." << endl;        else    cout << "<" << s << ">" << " is not acceptable." << endl;        s = "";    }    return 0;}