[Leetcode]398. Random Pick Index

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题目:

Given an array of integers with possible duplicates, randomly output the index of a given target number. You can assume that the given target 

number must exist in the array.

Note:
The array size can be very large. Solution that uses too much extra space will not pass the judge.

Example:

int[] nums = new int[] {1,2,3,3,3};Solution solution = new Solution(nums);// pick(3) should return either index 2, 3, or 4 randomly. Each index should have equal probability of returning.solution.pick(3);// pick(1) should return 0. Since in the array only nums[0] is equal to 1.solution.pick(1);


代码:

1.第一种写法

public class Solution {

    private int[]nums;
    Random random =new Random();
    public Solution(int[] nums) {
       this.nums = nums;
    }
    
    public int pick(int target) {
        ArrayList<Integer>list = new ArrayList<Integer>();
        for(int i = 0 ; i < nums.length;i++){
            if(nums[i]==target){
                list.add(i);
            }
        }
        //把目标值存放在list中,然后等概率的返回
        return list.get(random.nextInt(list.size()));
    }
}


/**
 * Your Solution object will be instantiated and called as such:
 * Solution obj = new Solution(nums);
 * int param_1 = obj.pick(target);

 */


2.第二种写法:

  1. public class Solution { // 417ms  
  2.     private int[] nums;  
  3.     private Random random;  
  4.   
  5.     public Solution(int[] nums) {  
  6.         this.nums = nums;  
  7.         this.random = new Random();  
  8.     }  
  9.   
  10.     public int pick(int target) {  
  11.         int result = -1;  
  12.         int count = 1;  
  13.         for (int i = 0; i < nums.length; i++) {  
  14.             if (nums[i] == target) {  
  15.                 if (random.nextInt(count) == 0) {  
  16.                     result = i;  
  17.                 }   
  18.                 count++;  
  19.             }  
  20.         }  
  21.         return result;  
  22.     }  
  23. }  
  24.   
  25. /** 
  26.  * Your Solution object will be instantiated and called as such: 
  27.  * Solution obj = new Solution(nums); 
  28.  * int param_1 = obj.pick(target); 
  29.  */  



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