【python】【leetcode】【算法题目387—First Unique Character in a String】
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一、题目描述
题目原文:
Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1.
(输入一个字符串,给出此串中非重复的字符,并返回其下标,若不存在则返回-1)
二、题目分析
思路:依次循环,判断当前字符在该串中出现的的次数,若为1则输出即可。
(用have_done列表存放已经判断过的元素,避免重复判断,用于优化时间)
三、Python代码
class Solution(object): def firstUniqChar(self, s): """ :type s: str :rtype: int """ have_done = [] for i in range(0, len(s)): if s[i] not in have_done: if s.count(s[i]) == 1: return i else: have_done.append(s[i]) else: continue return -1
四、其他
题目链接:https://leetcode.com/problems/first-unique-character-in-a-string/
Runtime: 228 ms
想法不够优化,欢迎大家留言交流~
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