LeetCode 190. Reverse Bits
来源:互联网 发布:java运行库安装 编辑:程序博客网 时间:2024/05/24 05:03
public class Solution { // you need treat n as an unsigned value public int reverseBits(int n) { int r = 0; for (int i = 0; i < 32; i++) { r += n & 1; n >>>= 1; if (i < 31) r <<= 1; } return r; }}
0 0
- 【LeetCode】190.Reverse bits
- LeetCode 190. Reverse Bits
- Leetcode 190. Reverse Bits
- 190. Reverse Bits LeetCode
- LeetCode *** 190. Reverse Bits
- LeetCode 190. Reverse Bits
- Leetcode-190. Reverse Bits
- Leetcode 190. Reverse Bits
- LeetCode-190.Reverse Bits
- [leetcode] 190. Reverse Bits
- Leetcode 190. Reverse Bits
- [Leetcode]190. Reverse Bits
- LeetCode 190. Reverse Bits
- [leetcode] 190. Reverse Bits
- leetcode 190. Reverse Bits
- [LeetCode] 190. Reverse Bits
- leetcode 190. Reverse Bits
- LeetCode 190. Reverse Bits
- mac android studio 快速查看方法说明注解的快捷键 直接点击fn+f1
- BOOL,int,float,指针变量 与“零值”比较的if语句
- 网卡中的MAC与PHY芯片定义
- 在Android原生中嵌入React Native,进而React Native调用原生
- eclipse中部署openfire4.0.4(最新版本) 源码后编译
- LeetCode 190. Reverse Bits
- jemalloc 3.6.0源码详解—[4]Thread caches
- 【Spring】Spring Framework Reference Documentation中文版1
- wiredtiger了解
- 9.5MATLAB for循环结构
- CUDA从入门到精通
- [HBase学习]HBase安装
- haproxy 基本维护命令和监控统计命令
- LeetCode 204 Count Primes题解