leetcode412 笔记

1. Fizz Buzz
   Write a program that outputs the string representation of numbers from 1 to n.
   But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and five output “FizzBuzz”.
   编写一个用字符串表示数字从1到n的程序。
   但是对于三的倍数，应该输出“Fizz”，对于五点倍数输出“Buzz”， 对于三和五的公倍数输出“FizzBuzz”。

class Solution {public:    vector<string> fizzBuzz(int n) {        vector<string> result;        for(int i=1;i<=n;i++){            if(i%3==0&&i%5!=0)                result.push_back("Fizz");            else if(i%3!=0&&i%5==0)                result.push_back("Buzz");            else if(i%3==0&&i%5==0)                result.push_back("FizzBuzz");            else                result.push_back(to_string(i));        }        return result;    }};

1、string to_string (int val);
2、字符串string用双引号，字符char用单引号哦～
（“a”是一个字符串，它包含字符a和\0，‘a’只表示字符a。字符串映射ascii码，其实就是数字。）

class Solution {public:    vector<string> fizzBuzz(int n) {        vector<string> result(n);//初始化为n个空字符串        for(int i=1; i<=n; ++i)        {            if(i%3 == 0)//是3            {                result[i-1] += "Fizz";//字符串的相加            }            if(i%5 == 0)//也是5            {                result[i-1] += "Buzz";            }            if(result[i-1] == "")//非3非5            {                result[i-1] += to_string(i);            }        }        return result;    }};