leetCode 数值

1 Reverse Integer
描述：整数反转
记忆：判断最小，反转

public int reverseInteger(int n) {        // Write your code here        if (n == Integer.MIN_VALUE) {            return 0;        }        int num = Math.abs(n);        int res = 0;        while (num != 0) {            if (res > (Integer.MAX_VALUE - num % 10) / 10) {                return 0;            }            res = res * 10 + num % 10;            num /= 10;        }        return n > 0 ? res : - res;    }