LeetCode每日一题——231. Power of Two

原题地址： 

https://leetcode.com/problems/power-of-two/

Fizz Buzz

描述：

Given an integer, write a function to determine if it is a power of two.

举例：

无

解题思路：

判断是否是2的次方数，并进行di'gu

作答：

//判断2的次方数public class PowerofTwo {public static void main(String[] args) {for (int i = 0; i < 1000; i++) {if (isPowerOfTwo(i)) {System.out.println(i);} }}static int num = 0;public static boolean isPowerOfTwo(double n) {  if (Math.pow(2, num) == n) {  num = 0;return true;} else if (Math.pow(2, num) < n) {num++;return isPowerOfTwo(n);} else { num = 0;return false;}     }}