进制之间的转换（java代码实现）

**
输入要求：
要求1.  此程序没有加以控制，输入时请输入正确的要求，比如需要将8进制的数转化为其它进制的数时，字符串中不能出现9.
要求2.  因为数据类型为int，数不能过大，过大会出现错误。（也可以将int类型改为long类型，范围会增大。）**

import java.util.Scanner;

public class Transform {

public static void main(String[] args) {    String str = null;    int num1 = 0,num2 = 0;    System.out.println("请输入要转化的字符串：");    Scanner reader_str = new Scanner(System.in);    if(reader_str.hasNext()){        str = reader_str.next();    }    System.out.println("请输入字符串的进制数：");    Scanner reader_num1 = new Scanner(System.in);    if(reader_num1.hasNext()){        num1 = reader_num1.nextInt();    }    System.out.println("请输入需要转化成的进制数：");    Scanner reader_num2 = new Scanner(System.in);    if(reader_num2.hasNext()){        num2 = reader_num2.nextInt();    }    StringBuffer result = anyToany(num1, num2, str);    System.out.println(result);}// 将number从10进制转化十六进制public static StringBuffer tenToSixteen(int number) {    StringBuffer str = new StringBuffer();    int shang = number;    int yu;    while (shang != 0) {        shang = number / 16;        yu = number % 16;        number = shang;        if (yu > 9) {            char form = (char) (yu - 10 + 'a');            str.append(form);        } else {            str.append(yu);        }    }    str.reverse();    return str;}// 将str从num进制转化到十进制public static int anyToTen(String str, int num) {    int sum = 0;    int num_after;    for (int i = str.length() - 1; i >= 0; i--) {        char c = str.charAt(i);        if ((int) c > 96) {// 如果c是个字母            num_after = c - 'a' + 10;        } else { // 如果c是个数字            num_after = c - '0';        }        /* System.out.println("c"+i+":   out:"+num_after); */        sum += num_after * Math.pow(num, str.length() - 1 - i);    }    return sum;}// 将number从十进制到num进制的转化public static StringBuffer tenToAny(int number, int num) {    StringBuffer str = new StringBuffer();    int shang = number;    int yu;    while (shang != 0) {        shang = number / num;        yu = number % num;        number = shang;        if (yu > 9) {            char form = (char) (yu - 10 + 'a');            str.append(form);        } else {            str.append(yu);        }    }    str.reverse();    return str;}// 将str从num1进制转化num2进制public static StringBuffer anyToany(int num1, int num2, String str) {    int first_form = anyToTen(str,num1); //先将str从num1进制转化为十进制    StringBuffer s = tenToAny(first_form, num2);//将十进制转化为num2进制    return s;}

}
测试截图：

在线进制转换网站：http://tool.oschina.net/hexconvert/