java中的List记录是否完全匹配方法

今天要说的是给List分组，然后用Map来封装，可能你看了以后还是有一些模糊。

先看一下项目结构图：

User类是一个VO类，主要逻辑还是在MapTestBak上面。

运行效果：

原理图：

1.在starsList中有两组人，共三人

2.在dolList中有一组人，共两人

3.经过marched操作，最后匹配到一组人到result中。即第一组人。

原理很简单。

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源码部分：

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/mapTest/src/com/b510/map/MapTestBak.java

  1 /**  2  *   3  */  4 package com.b510.map;  5   6 import java.util.ArrayList;  7 import java.util.HashMap;  8 import java.util.List;  9 import java.util.Map; 10  11 /** 12  * @author Hongten 13  * @created Apr 28, 2014 14  */ 15 public class MapTestBak { 16  17     public static void main(String[] args) { 18         mapTest(); 19     } 20  21     /** 22      *  23      */ 24     private static void mapTest() { 25         // starsList 26         List<User> starsList = getStarsList(); 27  28         // dolList 29         List<User> dolList = getDolList(); 30  31         Map<String, List<User>> map = groupingHandler(starsList); 32         // test 33         groupingHandlerTest(map); 34  35         System.out.println("======= group finished ======="); 36         List<Map<String, List<User>>> compareResultList = compare(dolList, map); 37         if(null != compareResultList){ 38             System.out.println(compareResultList.size()); 39         } 40     } 41  42     /** 43      * @param dolList 44      * @param map 45      */ 46     private static List<Map<String, List<User>>> compare(List<User> dolList, Map<String, List<User>> map) { 47         List<Map<String, List<User>>>  tempList = new ArrayList<Map<String, List<User>>>(); 48         if (null != map) { 49             for (String key : map.keySet()) { 50                 List<User> u = map.get(key); 51                 List comList = new ArrayList(); 52                 boolean comFlag = true; 53                 for (User us : u) { 54                     List comList1 = new ArrayList(); 55                     for (User ul : dolList) { 56                         if (us.getGroupNO() == ul.getGroupNO() && us.getName().trim().equals(ul.getName().trim())) { 57                             comList1.add(1); 58                         } else { 59                             comList1.add(0); 60                         } 61                     } 62                     if (comList1.contains(1)) { 63                         // name has existed. 64                         comList.add(1); 65                     } else { 66                         comList.add(0); 67                     } 68                 } 69                 if (comList.contains(0)) { 70                     comFlag = false; 71                 } 72                 // print out the match result in the console. 73                 printMatchResult(tempList, key, u, comFlag); 74             } 75         }else{ 76             System.out.println("map is null!"); 77         } 78         return tempList; 79     } 80  81     /** 82      * @param tempList 83      * @param key 84      * @param u 85      * @param comFlag 86      */ 87     private static void printMatchResult(List<Map<String, List<User>>> tempList, String key, List<User> u, boolean comFlag) { 88         if (comFlag) { 89             // do something 90             System.out.println("group : " + key + " compared!\n Detail:"); 91             System.out.println("================"); 92             for (User ut : u) { 93                 System.out.println(ut.getGroupNO() + ", " + ut.getName()); 94             } 95             System.out.println("================"); 96             Map<String, List<User>> tempMap = new HashMap<String, List<User>>(); 97             tempMap.put(key, u); 98             tempList.add(tempMap); 99         } else {100             System.out.println("group : " + key + " NOT compared!");101         }102     }103 104     /**105      * @param map106      */107     private static void groupingHandlerTest(Map<String, List<User>> map) {108         if (null != map) {109             for (String key : map.keySet()) {110                 List<User> u = map.get(key);111                 for (User u1 : u) {112                     System.out.println(u1.getGroupNO() + ", " + u1.getName());113                 }114             }115         }116     }117 118     /**119      * @param starsList120      * @param map121      */122     private static Map<String, List<User>> groupingHandler(List<User> starsList) {123         Map<String, List<User>> map = new HashMap<String, List<User>>();124         for (User stars_user : starsList) {125             String no = String.valueOf(stars_user.getGroupNO());126             if (map.isEmpty()) {127                 List<User> l = new ArrayList<User>();128                 l.add(stars_user);129                 map.put(no, l);130             } else {131                 List<User> user_map = map.get(no);132                 if (null == user_map || "".equals(user_map)) {133                     List<User> l = new ArrayList<User>();134                     l.add(stars_user);135                     map.put(no, l);136                 } else {137                     List<User> l = map.get(no);138                     l.add(stars_user);139                     map.put(no, l);140                 }141             }142         }143         return map;144     }145 146     /**147      * @param dolList148      */149     private static List<User> getDolList() {150         List<User> dolList = new ArrayList<User>();151         User user_B1_dol = new User(1, "MRS KON");152         User user_A_dol = new User(1, "KON SUE");153         dolList.add(user_B1_dol);154         dolList.add(user_A_dol);155         return dolList;156     }157 158     /**159      * @param starsList160      */161     private static List<User> getStarsList() {162         List<User> starsList = new ArrayList<User>();163         User user_B1 = new User(1, "MRS KON");164         User user_A = new User(1, "KON SUE");165         User user_B2 = new User(2, "MRS KON");166         User user_C = new User(2, "LON MEI");167         starsList.add(user_B1);168         starsList.add(user_A);169         starsList.add(user_B2);170         starsList.add(user_C);171         return starsList;172     }173 }

/mapTest/src/com/b510/map/User.java

 1 /** 2  *  3  */ 4 package com.b510.map; 5  6 /** 7  * @author Hongten 8  * @created Apr 28, 2014 9  */10 public class User {11 12     private int groupNO;13     private String name;14 15     public int getGroupNO() {16         return groupNO;17     }18 19     public User(int groupNO, String name) {20         this.groupNO = groupNO;21         this.name = name;22     }23 24     public void setGroupNO(int groupNO) {25         this.groupNO = groupNO;26     }27 28     public String getName() {29         return name;30     }31 32     public void setName(String name) {33         this.name = name;34     }35 36 }

我想要记录一下的是方法：compare(List<User> dolList, Map<String, List<User>> map)

 1 private static List<Map<String, List<User>>> compare(List<User> dolList, Map<String, List<User>> map) { 2         List<Map<String, List<User>>>  tempList = new ArrayList<Map<String, List<User>>>(); 3         if (null != map) { 4             for (String key : map.keySet()) { 5                 List<User> u = map.get(key); 6                 List comList = new ArrayList(); 7                 boolean comFlag = true; 8                 for (User us : u) { 9                     List comList1 = new ArrayList();10                     for (User ul : dolList) {11                         if (us.getGroupNO() == ul.getGroupNO() && us.getName().trim().equals(ul.getName().trim())) {12                             comList1.add(1);13                         } else {14                             comList1.add(0);15                         }16                     }17                     if (comList1.contains(1)) {18                         // name has existed.19                         comList.add(1);20                     } else {21                         comList.add(0);22                     }23                 }24                 if (comList.contains(0)) {25                     comFlag = false;26                 }27                 // print out the match result in the console.28                 printMatchResult(tempList, key, u, comFlag);29             }30         }else{31             System.out.println("map is null!");32         }33         return tempList;34     }

在这个方法中，这里使用了两个List（即：comList, comList1）来记录是否完全匹配。

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多读一些书，英语很重要。

More reading,and english is important.

I'm Hongten