程序题——链表倒数结点

编写一个程序，实现输出链表中倒数第K个结点

ListNode * FindKthToTail(LisNode *head, unsigned int k){    if(head == NULL || K == 0)            //入口参数检查！！！    {        return NULL;    }    int i;    ListNode *pAhead = head;    ListNode *pBehind = NULL;    for(i = 0; i < k - 1; ++i)    {        if(pAhead->next != NULL)        {             pAhead = pAhead->next;        }        else       {           return NULL;       }    }    pBehind = head;    while(pAhead->next != NULL)    {        pAhead = pAhead->next;        pBehind = pBehind->next;    }    Return pBehind;}