459. Repeated Substring Pattern
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public class Solution { public boolean repeatedSubstringPattern(String str) { int l=str.length(); for(int i=l/2;i>=1;i--) { if(l%i==0)//如果l是i的整数倍 { int m=l/i;//求出倍数 String s=str.substring(0, i); StringBuilder sb=new StringBuilder(); for(int j=0;j<m;j++) { sb.append(s); } if(sb.toString().equals(str)) return true; } } return false; }}
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- 459. Repeated Substring Pattern
- 459. Repeated Substring Pattern
- 459. Repeated Substring Pattern*
- 459. Repeated Substring Pattern
- 459. Repeated Substring Pattern
- 459. Repeated Substring Pattern
- 459. Repeated Substring Pattern
- 459. Repeated Substring Pattern
- 459. Repeated Substring Pattern
- 459. Repeated Substring Pattern
- 459. Repeated Substring Pattern
- 459. Repeated Substring Pattern
- 459. Repeated Substring Pattern
- 459. Repeated Substring Pattern
- 459. Repeated Substring Pattern
- 459. Repeated Substring Pattern
- 459. Repeated Substring Pattern
- 459. Repeated Substring Pattern
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