PAT A1065

1065. A+B and C (64bit) (20)

Given three integers A, B and C in [-2⁶³, 2⁶³], you are supposed to tell whether A+B > C.

Input Specification:

The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:

For each test case, output in one line "Case #X: true" if A+B>C, or "Case #X: false" otherwise, where X is the case number (starting from 1).

Sample Input:

31 2 32 3 49223372036854775807 -9223372036854775808 0

Sample Output:

Case #1: falseCase #2: trueCase #3: false

实现代码如下：

#include <iostream>#include <cstdio>using namespace std;int main() {  long long a, b , c, d;  int n;  cin >> n;  for(int i = 1; i <= n; i++){    cin >> a >> b >> c;    d = a + b;    if(a > 0 && b > 0 && d < 0)      printf("Case #%d: true\n", i);    else if(a < 0 && b < 0 && d >= 0)      printf("Case #%d: false\n", i);    else if(d > c)      printf("Case #%d: true\n", i);    else      printf("Case #%d: false\n", i);  }  return 0;}