文件的转置

Problem L7_F3_Z1

Write a program that reverses the order of integers stored in a binary file L7_F3_Z1.dat. Do not useadditional files.

#include<cstdio>#include<fstream>#include<iomanip>#include<iostream>using namespace std;//Ö®ËůŇÔgcountĘäłö10Ćäʵ˛»ĘÇ10Ł¬ĆäʵĘÇ16.ŇňÎŞµ±ÓĂŐâ¸ölen×÷forŃ­»·µÄʱşňĆäʵĘÇ16 int main(){ifstream ifs("L8_F3_Z1.dat",ios::binary);if(!ifs){cout<<"Error opening file\n";return 1; } int len;unsigned char txt[100][4];int number[1000];int count=0;cout<<sizeof(int)<<endl;string sentence; ifs.seekg(0,ios::end);cout<<"The whole chars of this file is "<<ifs.tellg()<<endl;//×îşóÍęłÉÖ»ĘǸÄÁËŐâŔď¶řŇŃŁ¬ĆäʵҲûÓĐ×öʲôŁ¬żÉÄÜľÍĘÇÓď·¨µÄÉčÖĂÎĘĚâ°É len=ifs.tellg()/4;ifs.seekg(0,ios::beg);while(count<len){//!ifs means what ifs.read(reinterpret_cast<char*>(&txt[count]),sizeof(int));//˝«¶Áȡµ˝µÄĘýÇżÖĆת»»łÉcharĐÍŁ¬ŇňÎŞŐâ¸ötxtĘÇcharĐÍÖ¸Őë cout<<"txt:"<<txt[count]<<endl;cout<<"txt1:"<<setfill('0')<<setw(2)<<hex<<static_cast<int>(txt[count][1]-'0')<<":";cout<<"txt2:"<<setfill('0')<<setw(2)<<hex<<static_cast<int>(txt[count][2]-'0')<<":";cout<<"txt3:"<<setfill('0')<<setw(2)<<hex<<static_cast<int>(txt[count][3]-'0')<<":";cout<<"txt4:"<<setfill('0')<<setw(2)<<hex<<static_cast<int>(txt[count][4]-'0')<<endl;//int txt1=(txt[1]-'0')<<12;//int txt2=(txt[2]-'0')<<8;//int txt3=(txt[3]-'0')<<4;//int txt4=txt[4]-'0';//number[count]=txt1+txt2+txt3+txt4;//cout<<number[count]<<endl;count++;}cout<<count<<endl;ifs.close();//before open it, clear all ofstream ofs("L8_F3_Z1.dat",ios::binary|ios::out|ios::trunc);if(!ofs){cout<<"Error opening file\n";return 1; } ofs.seekp(0,ios::end);int nowPosition=ofs.tellp();cout<<"The position now is "<<nowPosition<<endl;ofs.seekp(0,ios::beg);for(int i=0;i<count;i++){ofs.seekp(i*4,ios::beg);ofs.write(reinterpret_cast<char*>(&txt[count-i-1]), sizeof(int));}ofs.close();return 0;}