Leetcode Reverse Bits
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题意：将二进制数到序。
思路：简单模拟。
class Solution {public: uint32_t reverseBits(uint32_t n) { uint32_t re = 0; for(int i =0; i < 32; ++ i) { uint32_t temp = n % 2; re <<= 1; re += temp; n /= 2; } return re; }}; 0 0
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