【leetcode】73. Set Matrix Zeroes【java】

Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place.

click to show follow up.

Follow up:

Did you use extra space?
A straight forward solution using O(mn) space is probably a bad idea.
A simple improvement uses O(m + n) space, but still not the best solution.

Could you devise a constant space solution?

Analysis

This problem should be solved in place, i.e., no other array should be used. We can use the first column and the first row to track if a row/column should be set to 0.

Since we used the first row and first column to mark the zero row/column, the original values are changed.

Specifically, given, the following matrix

this problem can be solved by following 4 steps:

Step 1:
First row contains zero = true;
First column contains zero = false;

Step 2: use first row and column to mark zero row and column.

Step 3: set each elements by using marks in first row and column.

Step 4: Set first column and row by using marks in step 1.

Java Solution

public class Solution {    public void setZeroes(int[][] matrix) {        int m = matrix.length;        int n = matrix[0].length;        Boolean first_row = false;        Boolean first_col = false;        //set first row and column zero or not        for (int i = 0; i < m; i++){            if (matrix[i][0] == 0){                first_col = true;                break;            }        }        for (int j = 0; j < n; j++){            if (matrix[0][j] == 0){                first_row = true;                break;            }                    }        //mark zeros on first row and column        for (int i = 1; i < m; i++){            for (int j = 1; j < n; j++){                if (matrix[i][j] == 0){                    matrix[0][j] = 0;                    matrix[i][0] = 0;                }            }        }        //use mark to set elements        for (int i = 1; i < m ; i++){            if (matrix[i][0] == 0){                for (int j = 1; j < n; j++){                    matrix[i][j] = 0;                }            }        }        for (int j = 1; j < n ; j++){            if (matrix[0][j] == 0){                for (int i = 1; i < m; i++){                    matrix[i][j] = 0;                }            }        }        //set first column and row        if (first_row){            for (int j = 0; j < n; j++){                matrix[0][j] = 0;            }        }        if (first_col){            for (int i = 0; i < m; i++){                matrix[i][0] = 0;            }        }    }}