c++实现ip是否在同一个网段的判断

来源：互联网发布：美国服装品牌知乎编辑：程序博客网时间：2024/04/29 15:56

废话不说直接贴代码：

ip的数据结构

typedef struct IP_Struct{//ip地址划分后各个域的值struct IpAdress_Struct{int first;  int second;  int third;  int forth;}IpAdress,*pIPAdress;//ip地址char szIPAdress[MAX_PATH];//子网掩码char szIPMask[MAX_PATH];IP_Struct(){strcpy(szIPAdress,"");strcpy(szIPMask,"");}IP_Struct(char szIPAdress[],char szIPMask[]){strcpy(this->szIPAdress,szIPAdress);strcpy(this->szIPMask,szIPMask);}}IP,*pIP;

判断ip是否合理及获取ip各个域的值

bool JudgeIp(char *szIP,IP_Struct::IpAdress_Struct *ipAdress){if (!szIP) return false;int index=0;int first=0,second=0,third=0,forth=0;   std::string ip=std::string(szIP);    first=atoi(&ip[index]);      if (first>255)          return false;if (ipAdress)ipAdress->first=first;        index++;      index=ip.find_first_of('.',index);      second=atoi(&ip[++index]);      if(second>255)          return false;  if (ipAdress)ipAdress->second=second;        index++;      index=ip.find_first_of('.',index);      third=atoi(&ip[++index]);      if(third>255)          return false;  if (ipAdress)ipAdress->third=third;    index++;      index=ip.find_first_of('.',index);      forth=atoi(&ip[++index]);      if(forth>255)          return false;  if (ipAdress)ipAdress->forth=forth;        return true;  }

判断是否同一网段

//-1 indicates ip格式错误，0表示不同网段，1表示同网段int IsSameNetworkSegment(char *szIPAdress,char *szMask,char *szIPAdresss1){if (!szIPAdress||!szMask||!szIPAdresss1) return false;    IP_Struct::IpAdress_Struct ip,ip1,mask;    if (JudgeIp(szIPAdress,&ip)&&JudgeIp(szIPAdresss1,&ip1)&&JudgeIp(szMask,&mask))    {        ip.first=ip.first & mask.first;              ip.second=ip.second & mask.second;              ip.third=ip.third & mask.third;              ip.forth=ip.forth & mask.forth;                ip1.first=ip1.first & mask.first;              ip1.second=ip1.second & mask.second;              ip1.third=ip1.third & mask.third;              ip1.forth=ip1.forth & mask.forth;                if(ip.first==ip1.first&&ip.second==ip1.second&&ip.third==ip1.third&&ip.forth==ip1.forth)                  return 1;            else                  return 0;}else    return -1;}

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