SQL中使用update inner join和delete inner join
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Update XXX set XXX where 这种写法大家肯定都知道,才发现update和delete居然支持inner join的update方式,这个在表间关联来做更新和删除操作非常有用.
列子:
update tb_User
set pass='' --此处pass前不要加 tb_User 别名usr
from tb_User usr
inner join tb_Address addr on usr.nAddressFK = addr.nAddressID
where usr.id=123
update tb_User set pass='' from tb_User usr inner join tb_Address addr on usr.nAddressFK = addr.nAddressID where usr.id=123
update的格式是
update t1 set t1.name=’Liu’ from t1 inner join t2 on t1.id = t2.tid
MySQL,ACCESS 写法如下:
UPDATE mem_world AS mw1 INNER JOIN mem_world AS mw2
ON mw1.parentid = mw2.wid
SET mw1.level = mw2.level
WHERE mw2.baseid = 107
AND mw2.parentid = 0
AND mw2.size > 1;
UPDATE mem_world AS mw1 INNER JOIN mem_world AS mw2 ON mw1.parentid = mw2.wid SET mw1.level = mw2.level WHERE mw2.baseid = 107 AND mw2.parentid = 0 AND mw2.size > 1;
on是表连接的筛选条件
就是说,表连接后,会产生一个类似于临时的视图这么一个东西
where是从这个临时的视图中筛选数据的
所以,你首先要搞清,你的所谓的2个条件属于哪一种
Delete
delete 语句也是类似
delete from t1 from t1 inner join t2 on t1.id = t2.tid
注意蓝色部分。
mysql:
- DELETE mwb FROM mem_world_building AS mwb INNER JOIN mem_world AS mw
- ON mwb.wid = mw.wid
- where mw.type between 11 and 15
- and baseid = 107
- and mw.parentid <> 0
- and mw.size > 1;
DELETE mwb FROM mem_world_building AS mwb INNER JOIN mem_world AS mw ON mwb.wid = mw.wid where mw.type between 11 and 15 and baseid = 107 and mw.parentid <> 0 and mw.size > 1;
下面是Oracle的:
- DELETE TABLE1 where KHID exists ( select KHID from table2 where FWDWID=8)
- DELETE TABLE1 where exists ( select 1 from table2 where and table1.khid=table2.khid and FWDWID=8);
- SQL中使用update inner join和delete inner join
- SQL中使用update inner join和delete inner join
- SQL中使用update inner join和delete inner join
- SQL中使用update inner join和delete inner join.
- SQL中使用update inner join和delete inner join.
- SQL中使用update inner join和delete inner join
- SQL中使用update inner join和delete inner join
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