蓝鸥iOS从零基础到精通就业－C语言入门 14结构体二

来源：互联网发布：sqlyog查看数据库密码编辑：程序博客网时间：2024/06/08 17:00

蓝鸥iOS从零基础到精通就业－C语言入门

（学习路径http://blog.csdn.NET/lanouluanbin/article/details/53518018）

14结构体二

#import <Foundation/Foundation.h>int main(int argc, const char * argv[]) {       struct dog {        int age;        char type[50];        char name[30];        float price;            };    typedef struct dog Dog;        //创建四只小狗    Dog dog1 = {4,"哈士奇","逗比哈",1000.0};    Dog dog2 = {6,"金毛","暖暖",1100.0};    Dog dog3 = {2,"阿拉斯加","水哥",1500.0};    Dog dog4 = {3,"泰迪","小黄",600.0};        //结构体数组    Dog dogs[4] = {dog1,dog2,dog3,dog4};    //打印阿拉斯加的价钱    float price = dogs[2].price;    printf("阿拉斯加的价格为%.2f\n",price);    //修改泰迪的价格    dogs[3].price = 900.0;    //打印数组中四只小狗的所有信息    for (int i = 0; i<4; i++) {        printf("小狗的信息是:%d %s %s %.2f\n",dogs[i].age,dogs[i].type,dogs[i].name,dogs[i].price);    }        //对数组中的四只小狗按照价钱升序排列    for (int i = 0; i<4-1; i++) {        for (int j = 0; j<4-i-1; j++) {            if (dogs[j].price > dogs[j+1].price) {                                Dog tempDog = dogs[j];                dogs[j] = dogs[j+1];                dogs[j+1] = tempDog;                            }        }    }    //遍历查看排序的结果    for (int i = 0; i<4; i++) {        printf("===小狗的信息是:%d %s %s %.2f\n",dogs[i].age,dogs[i].type,dogs[i].name,dogs[i].price);    }        //1结构体内存分配    struct stu {        char a;//1        int b;//4        char c;//1        long d;//8        char e[20];//20        float f;//4    };    struct stu s1 = {0};    printf("所占字节数为%ld\n",sizeof(s1));    //2结构体的嵌套            return 0;}

0 0